It has been hinted by the author that this "thermal load" is actually a piece of the sun's photosphere that has been teleported to that location: "Exactly how strong is the Level 9? In general, what kind of weapon is it? There are three clues. First, (more than Killy's gun) it is the ultimate (however seemingly uncontrollable) weapon. Next, the effect from the destructive "Thermal Load" spreads across surfaces. Finally, the energy of Killy's gun does not interfere with it. By the way, in "BLAME!" there are a whole lot of things that seem to be the absolutely highest level weapon, but as for something that can compare to the Level 9 one, there is only Mensaab's transmission (or rather, the situation after the transfer). Given that, the inference of it as a weapon is absolutely true, but what I think of as a weapon is the transfer that carried over the surface of another world. With that assumption, maybe it was the surface of the sun?" (source: www.randomisgod.com/blame/Artbook85.html)
- Now, from several visual clues found in some images, I have managed to approximate the size of that thermal load (from both the following images and the images under the "The Feat" tab. Note that, story-wise, the following images' sequence should be in reverse):
P = ε*A*σ*(Tblack body^4 - Tsurroundings^4) P = power radiated from the black body J/s ε = emissivity of the black body = 1 (Stars are not perfect black bodies, but this is for simplicity's sake) σ = Stefan-Boltzmann constant = 5.670373*10^-8 W*m^-2*K^-4 A = surface area of the black body (surface area of a clyinder) = 7821117.63936 metres^2 Tblack body = temperature of the black body = 5778 K (Temperature of the sun's surface) Tsurroundings = temperature of the surroundings = 298 K (standard ambient temperature)
P = 1*7821117.63936*(5.670373*10^-8)*(5778^4-298^4) = 4.9429649*10^14 J/s
I don't know how long the thermal load lingered, and so I cannot calculate its actual destructive capacity, for now, that is. I'll come back to that point later.
Eva01, One correction: the body is not in a vacuum, but rather in a medium. While it does radiate that amount, it also absorbs an amount of power from the surroundings, so if you want to know the heat rate, then you would have to subtract that amount.
тиваненк Can you elaborate? I am pretty damn rusty; I'm not saying you're wrong, I just don't remember the "why" of it. Why would subtracting the amount of power absorbed by the thermal load from its surroundings from the power it actually generates give us the true yield? Or did you mean that I should subtract the amount of power absorbed by the surroundings? In that case, I wouldn't mind not doing it, since I made this calc to approximate Killy's durability who was at the very center of that thermal load.
Old Man Dream: Before jumping into Cinderella, found a means to see Make Mine Music. Did have to literally jump around between several different streaming sites to see all its segments. But nearly done. Not sure if I'll get around to reviewing it tonight. But...
Sept 25, 2020 1:49:38 GMT
Old Man Dream: ...will at least get a review for it up by tomorrow at the latest.
Sept 25, 2020 1:49:54 GMT
Taka: That's interesting. Some sites list Attack on Titan Final Season as Winter 2021 or Fall 2020 due to it being aired in Dec 7, 2020.
Sept 25, 2020 3:03:56 GMT